golang time包t.After的坑

代码如下

package main

import (
    "fmt"
    "sync"
    "time"
)

func main() {
    const FORMAT = "2006-01-02 15:04:05"
    var a = new(sync.Map)
    b := time.Now()
    fmt.Println(b.Location())
    a.Store("a", b)
    //c, _ := a.Load("a")
    fmt.Println(b.Format(FORMAT))
    time.Sleep(time.Second * 10)
    after := time.Hour * 5
    //t, ok := c.(time.Time); ok &&
    t := b
    if t.Add(after).After(time.Now()) {
        fmt.Println(t.Unix(), "\n", time.Now().Unix())
        fmt.Println(t.Add(after).Format(FORMAT), " 大于 ", time.Now().Format(FORMAT))
    } else {
        fmt.Println(t.Add(after).Format(FORMAT), " 小于 ", time.Now().Format(FORMAT))
    }
}

执行到time.Sleep(time.Second * 10)时如果修改当前时间为1天后，下面的After会判断错误,下面是输出结果

Local
2019-07-11 08:45:23
1562805923 
 1562856331
2019-07-11 13:45:23  大于  2019-07-11 22:45:31

如果t加上Local就没有问题，t.After函数的判断方式有问题