Golang算法：二叉树前序，中序，后序非递归遍历算法

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这是一个创建于的文章，其中的信息可能已经有所发展或是发生改变。

本文主要介绍了二叉树前序，中序，后序非递归遍历算法

import (
   "container/list"
)
// Binary Tree
type BinaryTree struct {
   Data  interface{}
   Left  *BinaryTree
   Right *BinaryTree
}
// Constructor
func NewBinaryTree(data interface{}) *BinaryTree {
   return &BinaryTree{Data: data}
}
// 先序遍历-非递归
func (bt *BinaryTree) PreOrderNoRecursion() []interface{} {
   t := bt
   stack := list.New()
   res := make([]interface{}, 0)
   for t != nil || stack.Len() != 0 {
      for t != nil {
         res = append(res, t.Data)//visit
         stack.PushBack(t)
         t = t.Left
      }
      if stack.Len() != 0 {
         v := stack.Back()
         t = v.Value.(*BinaryTree)
         t = t.Right
         stack.Remove(v)
      }
   }
   return res
}
// 中序遍历-非递归
func (bt *BinaryTree) InOrderNoRecursion() []interface{} {
   t := bt
   stack := list.New()
   res := make([]interface{}, 0)
   for t != nil || stack.Len() != 0 {
      for t != nil {
         stack.PushBack(t)
         t = t.Left
      }
      if stack.Len() != 0 {
         v := stack.Back()
         t = v.Value.(*BinaryTree)
         res = append(res, t.Data)//visit
         t = t.Right
         stack.Remove(v)
      }
   }
   return res
}
// 后序遍历-非递归
func (bt *BinaryTree) PostOrderNoRecursion() []interface{} {
   t := bt
   stack := list.New()
   res := make([]interface{}, 0)
   var preVisited *BinaryTree
   for t != nil || stack.Len() != 0 {
      for t != nil {
         stack.PushBack(t)
         t = t.Left
      }
      v   := stack.Back()
      top := v.Value.(*BinaryTree)
      if (top.Left == nil && top.Right == nil) || (top.Right == nil && preVisited == top.Left) || preVisited == top.Right{
         res = append(res, top.Data)//visit
         preVisited = top
         stack.Remove(v)
      }else {
         t = top.Right
      }
   }
   return res
}
func main() {
   t := NewBinaryTree(1)
   t.Left  = NewBinaryTree(3)
   t.Right = NewBinaryTree(6)
   t.Left.Left = NewBinaryTree(4)
   t.Left.Right = NewBinaryTree(5)
   t.Left.Left.Left = NewBinaryTree(7)
   fmt.Println(t.PreOrderNoRecursion())
   fmt.Println(t.InOrderNoRecursion())
   fmt.Println(t.PostOrderNoRecursion())
}

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