算法的细节可以参考网上的资料或数据结构的相关教材,这里直接上代码了~
鉴于本人技艺浅陋,有的地方写的可能不合理,代码略长,如果有改进之处,请留言指点,算法本身测试过了:
package main import ( "fmt" ) func GetNextValueArray(sub []byte) (next []int) { var ( length int = len(sub) middle int compare_left int compare_right int match_count int ) next = make([]int, length) next[0] = 0 next[1] = 0 for i := 2; i < length; i++ { middle = i / 2 match_count = 0 if i%2 == 0 { for j := 0; j < middle; j++ { compare_left = 0 compare_right = i - 1 - j for compare_left <= j { if sub[compare_left] != sub[compare_right] { break } compare_left++ compare_right++ } if compare_left == j+1 { match_count++ } } next[i] = match_count } else { for j := 0; j <= middle; j++ { compare_left = 0 compare_right = i - 1 - j for compare_left <= j { if sub[compare_left] != sub[compare_right] { break } compare_left++ compare_right++ } if compare_left == j+1 { match_count++ } } next[i] = match_count } } return next } func ReviseNextValueArray(next []int) []int { var length int = len(next) for i := 2; i < length; i++ { if next[i] == next[next[i]] { next[i] = next[next[i]] } } return next } //在content中的start-end之间寻找sub子串 //成功返回匹配成功的起始下标,匹配失败则返回-1 func KMP(content []byte, start_index int, end_index int, sub []byte) (index int) { var ( next []int = ReviseNextValueArray(GetNextValueArray(sub)) sub_index int = 0 sub_length int = len(sub) ) for i := start_index; i <= end_index; i++ { if content[i] == sub[sub_index] { match_start := i for j := sub_index; j <= sub_length; j++ { if j == sub_length { return match_start - sub_index } if i >= end_index || content[i] != sub[j] { sub_index = next[j] break } i++ } } } return -1 } func main() { content := []byte("why every programming language use the hello world as the first test???") sub := []byte("hello world") fmt.Println(KMP(content, 0, len(content)-1, sub)) }
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