模式特点：通过吧不变的行为搬到父类，去除子类中的重复代码。
程序实例：考试时使用同一种考卷（父类），不同学生上交自己填写的试卷（子类方法的实现）
package main
import (
"fmt"
)
type TestPaper struct {
child interface{}
}
func (t *TestPaper) testQuestion1() {
fmt.Println("杨过得到，后来给了郭靖，练成倚天剑、屠龙刀的玄铁可能是[] a.球磨铸铁 b.马口铁 c.高速合金钥 d.碳素纤维")
fmt.Println("答案：", t.child.(Answers).answer1())
}
func (t *TestPaper) testQuestion2() {
fmt.Println("杨过、程英、陆无双铲除了情花.造成[] a.使这种植物不再害人 b.使一种珍稀物种灭绝 c.破坏了那个生物圈的生态平衡 d.造成该地区沙漠化")
fmt.Println("答案：", t.child.(Answers).answer2())
}
func (t *TestPaper) testQuestion3() {
fmt.Println("蓝凤凰致使华山师徒、桃谷六仙呕吐不止，如果你是大夫，会给他们开什么药[] a.阿司匹林 b.牛黄解毒片 c.氟呱酸 d.让他们喝大量的生牛奶 e.以上全不对")
fmt.Println("答案：", t.child.(Answers).answer3())
}
type Answers interface {
answer1() string
answer2() string
answer3() string
}
type TestPaperA struct {
TestPaper
}
func NewTestPaperA() *TestPaper {
paper := &TestPaper{}
var answer Answers = &TestPaperA{}
paper.child = answer
return paper
}
func (t *TestPaperA) answer1() string {
return "b"
}
func (t *TestPaperA) answer2() string {
return "c"
}
func (t *TestPaperA) answer3() string {
return "a"
}
type TestPaperB struct {
TestPaper
}
func NewTestPaperB() *TestPaper {
paper := &TestPaper{}
var answer Answers = &TestPaperB{}
paper.child = answer
return paper
}
func (t *TestPaperB) answer1() string {
return "c"
}
func (t *TestPaperB) answer2() string {
return "a"
}
func (t *TestPaperB) answer3() string {
return "a"
}
func main() {
studentA := NewTestPaperA()
studentA.testQuestion1()
studentA.testQuestion2()
studentA.testQuestion3()
studentB := NewTestPaperB()
studentB.testQuestion1()
studentB.testQuestion2()
studentB.testQuestion3()
}
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