Why does Go's Rand package provide a function to smaple from the Zipf Distribution?

polaris · · 358 次点击    
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<p>Link here:</p> <p><a href="https://golang.org/pkg/math/rand/#Zipf">https://golang.org/pkg/math/rand/#Zipf</a></p> <p>Seems fairly arbitrary... No Gaussian?</p> <hr/>**评论:**<br/><br/>jlund3: <pre><p>For sampling from a Gaussian, <a href="https://golang.org/pkg/math/rand/#NormFloat64">NormFloat64</a> has you covered. Just multiply the Normal distribution by your standard deviation and add in your mean.</p></pre>fancy_pantser: <pre><p>As for why it provides Zipf distributions: back in 12/2009 (long before Go 1, just a month after it was announced to the public), William Josephson added it with <a href="https://github.com/golang/go/commit/52114724b779d2826746dfc3c2475f659bbd7961" rel="nofollow">this commit</a> and we see some feedback in <a href="https://codereview.appspot.com/176070" rel="nofollow">this review</a> but no reasoning on why he wanted to add it. The <a href="http://golang-nuts.narkive.com/7cjy5i2N/release-2009-12-22" rel="nofollow">release notes</a> mention it but no reason either.</p> <p>I can only imagine that Googlers wanted to have it in there because Zipf&#39;s law is often used in Natural Language Processing (NLP) and simulation thereof. The zeta distribution has many other uses, of course.</p> <blockquote> <p>Zipf&#39;s law states that given some corpus of natural language utterances, the frequency of any word is inversely proportional to its rank in the frequency table.</p> </blockquote></pre>

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