<p>This worked the way I had an intuition it would;</p>
<pre><code>package main
import (
"fmt"
"os"
"strconv"
)
func main() {
a, _ := strconv.Atoi(os.Args[1])
b, _ := strconv.Atoi(os.Args[2])
x(y(a, b))
}
func y(a, b int) (int, int) {
return a+b, a*b
}
func x(i, j int) {
fmt.Printf("Got %d, %d arguments\n", i, j)
}
</code></pre>
<p>Are the internals of returning multiple values from a function related to the internals of how multiple arguments get passed to a function?</p>
<hr/>**评论：**<br/><br/>anossov: <pre><p><a href="https://golang.org/ref/spec#Calls">https://golang.org/ref/spec#Calls</a></p>
<blockquote>
<p>As a special case, if the return values of a function or method g are equal in number and individually assignable to the parameters of another function or method f, then the call <code>f(g(parameters_of_g))</code> will invoke f after binding the return values of g to the parameters of f in order. The call of f must contain no parameters other than the call of g, and g must have at least one return value.</p>
</blockquote></pre>peterbourgon: <pre><p><del>A function that returns multiple values needs to have those values assigned to variables (or thrown away with underscore). You can't use a function call that returns 2 arguments as a parameter to a function that takes 2 arguments; you need to use intermediary variables.</del></p>
<p>This specific thing is special-cased, as is pointed out above. Mea culpa.</p></pre>ChristophBerger: <pre><p>OP's code <a href="https://play.golang.org/p/fgtGvCQiFaH" rel="nofollow">does work</a>...</p></pre>peterbourgon: <pre><p>Whoops! You're right, it's special cased, as <a href="/u/anossov" rel="nofollow">/u/anossov</a> points out above. Mea culpa.</p></pre>
