Newbie question about range

polaris · · 406 次点击    
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<p><em>The Go Programming Language</em> by D&amp;K states <code>range</code> produces a pair of values: the index and the value of the element at that index. However, it seems the index and the value iterate separately?</p> <p>For example:</p> <pre><code>for index, value := range os.Args[1:] { fmt.Println(index, value) } </code></pre> <p>Passing <code>arg1 arg2</code>:</p> <pre><code>0 arg1 1 arg2 </code></pre> <p>Since the value of index <code>1</code>/<code>2</code> is <code>arg1</code>/<code>arg2</code>, does any change from <code>[0:]</code> in a range therefore require an adjustment to the index (such as using <code>index+1</code> for <code>range os.Args[1:]</code>) to get the real index for each value?</p> <hr/>**评论:**<br/><br/>jcbwlkr: <pre><p>When you do <code>os.Args[1:]</code> you&#39;re re-slicing os.Args into a new slice and then <code>range</code>ing over that new slice. The new slice has indices starting at 0.</p></pre>thegopl: <pre><p>Thanks!</p></pre>pierrrre: <pre><p><a href="http://play.golang.org/p/UqVOPKo5D9" rel="nofollow">http://play.golang.org/p/UqVOPKo5D9</a></p></pre>rafailong: <pre><p>I think that the value of index o is the name of the program that is executed.</p></pre>

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