[Update] Ok. Again, Why I cannot mutate a slice inside another function?

xuanbao · · 405 次点击    
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<p>On the code I&#39;m working on I&#39;m <a href="https://play.golang.org/p/Z0rxJ_4N6X" rel="nofollow">experiencing this behavior</a> where I mutate the element of a <code>Struct</code> and the element seems changed but the value of the element changed, in the struct, is not!</p> <p>I&#39;m obviously missing something as I assumed that iterating over the element of the structure mutating it, the structure will reflect this as well. Is Go copying the element of the structure and passing it&#39;s value to my function, which in turn mutates the copy and not the original, right?</p> <p>Worst thing is that I have to run the function that mutates the element of the structure concurrently, I&#39;m afraid that what I want to achieve is possible but only it wouldn&#39;t be &#34;thread safe&#34;.</p> <p>If you down vote this post, please explain at least why. Thank you!</p> <hr/>**评论:**<br/><br/>binaryblade: <pre><p>because the local in the for loop is a copy of the object in your slice of slices. When you modify the copy it does not modify the object in your slice of slices</p> <p>edit: <a href="https://play.golang.org/p/IkODYcAmie" rel="nofollow">here</a></p></pre>shackra: <pre><p>Silly me, thank you!</p></pre>bscharm: <pre><p>when performing range you are working with a copy of the values from your struct Prueba. you can see this by logging the address of n versus the address of p.Lista[i] where i is the current index in your iteration.</p></pre>shackra: <pre><p>ah! my suspicion was confirmed then, thanks!</p></pre>tgulacsi: <pre><p>See <a href="https://play.golang.org/p/K6o7gT5YfB" rel="nofollow">https://play.golang.org/p/K6o7gT5YfB</a> What do you write concurrently?</p></pre>

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