Can't seem to understand what this function is doing...

xuanbao · · 349 次点击    
这是一个分享于 的资源,其中的信息可能已经有所发展或是发生改变。
<p>This is in <code>pool.go</code>. Originally I was trying to understand how pool.get worked. It brought me down a rabbit hole and I ran into this</p> <pre><code>func indexLocal(l unsafe.Pointer, i int) *poolLocal { return &amp;(*[1000000]poolLocal)(l)[i] } </code></pre> <p>What is it doing? initializing an array of size 1000000 of poolLocal. and then ... ?</p> <hr/>**评论:**<br/><br/>hlidotbe: <pre><p>Someone correct me but if I read that correctly it:</p> <ul> <li>&#34;cast&#34; <code>l</code> to a pointer to an array of 1000000 pool local (I guess since it&#39;s an unsafe pointer the compiler is OK with that)</li> <li>returns the address of the pool local item at index <code>i</code></li> </ul> <p>The large array size is to avoid tripping whatever boundary check the compiler is inserting I assume. There&#39;s no actual array of that size. </p></pre>lems2: <pre><p>ty!</p></pre>itsmontoya: <pre><p>You nailed it. One thing to note, this code is changing very soon. If you check tip, they recently improved pool performance.</p></pre>

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