Integers with over 1000 digits

<p>I am given a number with 1000 digits and was wondering if there&#39;s a simple way to store the individual digits.</p> <p>I tried the obvious thing of letting x = (large number) and the program broke down because the number was clearly too large. </p> <hr/>**评论：**<br/><br/>pdq: <pre><p><a href="https://golang.org/pkg/math/big/" rel="nofollow">https://golang.org/pkg/math/big/</a></p></pre>barsonme: <pre><p>What are you intending to do with this number?</p></pre>DJysyed: <pre><p>I want to look at all the products of 13 consecutive digits of the number and determine the largest of them</p></pre>barsonme: <pre><p>I&#39;d just keep it as a string, then. or []byte.</p></pre>jerf: <pre><p>Yes. A digit&#39;s value is that byte - 48, which you can see from an <a href="http://www.asciitable.com/" rel="nofollow">ASCII table</a>. The best thing to do would be to clean it up front and do one pass to convert the digits into their numerical values, then un-convert them on the way back out to print the answer.</p> <p>There&#39;s no point un-base-10&#39;ing the number with a bignum library just to have to sit there and manually re-base-10 the number to process it by digits when the initial input already had it broken out by base 10 digits, just with 48 added to each digit....</p></pre>sajattack: <pre><p><a href="https://github.com/sajattack/go-euler/blob/master/08/main.go" rel="nofollow">https://github.com/sajattack/go-euler/blob/master/08/main.go</a></p></pre>