以下是利用协程计算1到100亿之间的所有数的和
package main
import (
"fmt"
"time"
"runtime"
)
var c = make(chan int)
func main() {
cores := runtime.NumCPU()
start := time.Now().UnixNano()
fmt.Println(cores)
runtime.GOMAXPROCS(cores)
he := 0
max, num := 10000000000, 10
for i := 0; i < num; i++ {
go sum((max / num) * i + 1, (max / num) * (i + 1), i)
}
for i := 0; i < num; i++ {
he = he + <-c
}
fmt.Println("he:", he)
fmt.Println("take times is : ", (time.Now().UnixNano() - start))
// time.Sleep(1000*time.Second)
}
func sum(min, max, number int) {
s := 0
// fmt.Println("min:", min, "max:", max, "|", number)
for i := min; i <= max; i++ {
s = s + i
}
// fmt.Println(s)
c <- s
}
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