为什么用指针取得的值是一样的呢？

为什么使用值传入，输出的是正确的，但使用指针传入，再取值，获得的值却是一样的呢？？？？ ```go package main import ( "fmt" "time" ) func tggg(p *int) { fmt.Printf("p = %p, v = %d\n", p, *p) } func tggg1(t int) { fmt.Printf("v = %d\n", t) } func main() { number := []int{1, 2, 3, 4, 5} for _, v := range number { go tggg1(v) go tggg(&v) } time.Sleep(5*time.Second) } ``` 输出结果： ``` v = 1 p = 0xc000084010, v = 5 v = 2 p = 0xc000084010, v = 5 v = 3 p = 0xc000084010, v = 5 v = 4 p = 0xc000084010, v = 5 v = 5 p = 0xc000084010, v = 5 ``` ---------------------------------------时间线--------------------------- 我有加了个sleep 输出就不一样了，怎么感觉从地址里取值有延时啊 ```go package main import ( "fmt" "time" ) func tggg(p *int) { fmt.Printf("p = %p, v = %d\n", p, *p) } func tggg1(t int) { fmt.Printf("v = %d\n", t) } func main() { number := []int{1, 2, 3, 4, 5} for k, v := range number { // go tggg1(v) switch k { case 0: time.Sleep(1*time.Second) go tggg(&v) case 1: time.Sleep(2*time.Second) go tggg(&v) case 2: time.Sleep(3*time.Second) go tggg(&v) case 3: time.Sleep(4*time.Second) go tggg(&v) case 4: time.Sleep(5*time.Second) go tggg(&v) } // go tggg(&v) } time.Sleep(5*time.Second) } ``` 输出结果： ``` = 0xc000084010, v = 2 p = 0xc000084010, v = 3 p = 0xc000084010, v = 4 p = 0xc000084010, v = 5 p = 0xc000084010, v = 5 ``` 但是为啥没有1 ，却有两个5呢？？？？？