请教大家一个问题
怎么不让222打印出来
可以用runtime.Goexit()停止当前Go协程
```
package main
import (
"log"
"runtime"
"time"
)
func main() {
cb := make(chan bool, 1)
go func() {
timer2 := time.NewTimer(time.Second * 3)
tick := time.Tick(time.Second * 5)
select {
case <-timer2.C:
runtime.Goexit() //超时后退出该Go协程
case <-tick: //模拟超时任务
log.Println(222) //处理业务代码
cb <- true
return
}
}()
log.Println()
timer := time.NewTimer(time.Second * 2)
select {
case <-timer.C:
log.Println("time out")
cb <- false
case tmp := <-cb:
log.Println(tmp)
}
time.Sleep(time.Second * 10)
log.Println(123)
}
```
#4
更多评论
```go
package main
import (
"log"
"time"
)
func main() {
cb := make(chan bool, 1)
go func() {
timer2 := time.NewTimer(time.Second * 5)
select {
case <-timer2.C:
log.Println(222)
cb <- true
case <-cb:
return
}
}()
log.Println()
timer := time.NewTimer(time.Second * 2)
select {
case <-timer.C:
log.Println("time out")
cb <- false
case tmp := <-cb:
log.Println(tmp)
}
time.Sleep(time.Second * 10)
log.Println(123)
}
```
#1
timer2 再定义一个的话没法执行逻辑代码吧
#2
今日阅读排行
一周阅读排行