为什么闭包函数，内输出全局变量地址不同。请教了。

结果，再发一次

2016-08-17 00:43:40 1471365820260269854 [Debug] t_Mutex.go:23 [Test_Mutex Beg] 2016-08-17 00:43:40 1471365820260280118 [Debug] t_Mutex.go:29 [g_pMutex=0XAEA460] 2016-08-17 00:43:40 1471365820260282767 [Debug] t_Mutex.go:35 [TestUse Beg] 2016-08-17 00:43:40 1471365820260284942 [Debug] t_Mutex.go:38 [pMutex=0XC82002C128] 2016-08-17 00:43:40 1471365820260287015 [Debug] t_Mutex.go:44 [TestUse End] 2016-08-17 00:43:40 1471365820260288973 [Debug] t_Mutex.go:48 [Test_Mutex End]

很正常，闭包和方法是一样的，你传入的参数是复制的，两个指针的地址自然不一样。但两个指针指向的值却是一样的，这是两个不同的概念。你可以在闭包内外，通过"p"格式指令，对比一下：

package main

import (

    "fmt"
    "sync"
)

var g_pMutex *sync.Mutex
var g_iCount int32

func main() {
    fmt.Println( "Test_Mutex Beg" )
    defer fmt.Println( "Test_Mutex End" )

    fmt.Println( "" )

    g_pMutex = new( sync.Mutex )
    fmt.Printf( "g_pMutex=%p \n", g_pMutex )
    fmt.Printf( "&g_pMutex=%p \n", &g_pMutex )

    g_iCount = 0

    pfnFunc := func ( pMutex *sync.Mutex ) {

        fmt.Println( "TestUse Beg" )
        defer fmt.Println( "TestUse End" )

        fmt.Printf( "pMutex=%p \n", pMutex )
        fmt.Printf( "&pMutex=%p \n", &pMutex )

        pMutex.Lock()
        defer pMutex.Unlock()

        g_iCount ++
    }

    pfnFunc( g_pMutex )
    fmt.Println("g_iCount=",g_iCount)
}