两个逻辑处理器处理两个goruntine并发运行时如何确定哪个goruntine先运行？

代码如下： func main() { // Allocate 1 logical processors for the scheduler to use. runtime.GOMAXPROCS(1) // Add a count of two, one for each goroutine. wg.Add(2) // Create two goroutines. fmt.Println("Create Goroutines") go printPrime("B") go printPrime("A") // Wait for the goroutines to finish. fmt.Println("Waiting To Finish") wg.Wait() fmt.Println("Terminating Program") } // printPrime displays prime numbers for the first 5000 numbers. func printPrime(prefix string) { // Schedule the call to Done to tell main we are done. defer wg.Done() next: for outer := 2; outer < 5000; outer++ { for inner := 2; inner < outer; inner++ { if outer%inner == 0 { continue next } } fmt.Printf("%s:%d\n", prefix, outer) } fmt.Println("Completed", prefix) } 运行结果如下： // Create Goroutines Waiting To Finish A:2 A:3 A:5 A:7 A:11 A:13 A:17 A:19 A:23 ... B:2 B:3 B:4999 Completed B A:3767 A:3769 ... Completed A Terminating Program 为什么会输出素数的时候先显示B:2 而不是先显示A:2？ go printPrime("B") go printPrime("A") 这两条goruntine的执行顺序是什么样子的？