如何实现通过列ID输出列名？

``` func ExcelConvertTitleToNum(s string) (res int) { res = 1 //输入验证 if s == "" { return 0 } ss := []byte(s) length := len(ss) fmt.Println() for i := 0; i < length; i++ { res = i*26 + int(ss[i]+1)%int('A') } return } ```

你这转换不对，当s="AAA"时你算出的结果是53，正确结果是703。我需要的是从703到AAA的转换。

折腾3个小时，你这26进制又满26不进1的，真难弄，一个思路，自己优化吧 ```golang func TestPrint(t *testing.T) { x := decimalToAny(703, 26) flag := false var y []byte for i:= range x{ if !flag { if x[i] == '0' { y = append(y,'Z') flag = true } else { if flag { if i==len(x)-1 && byte(x[i]) == '1'{ break } if byte(x[i]) == '1' { y = append(y,'Z') }else { y = append(y,twentySix[x[i]]) flag = false } } else { y = append(y,twentySix[x[i]]) } } }else { if i==len(x)-1 && byte(x[i]) == '1'{ break } if byte(x[i]) == '1'{ y = append(y,'Z') } else { if byte(x[i]) =='0' { y = append(y,'Y') }else { y = append(y,twentySix[x[i-1]]) flag = false } } } } for i:= len(y)-1;i>=0; i--{ fmt.Print(string(y[i])) } fmt.Println() } var tenToAny = map[int]byte{0: '0', 1: '1', 2: '2', 3: '3', 4: '4', 5: '5', 6: '6', 7: '7', 8: '8', 9: '9', 10: 'a', 11: 'b', 12: 'c', 13: 'd', 14: 'e', 15: 'f', 16: 'g', 17: 'h', 18: 'i', 19: 'j', 20: 'k', 21: 'l', 22: 'm', 23: 'n', 24: 'o', 25: 'p', 26: 'q', 27: 'r', 28: 's', 29: 't', 30: 'u', 31: 'v', 32: 'w', 33: 'x', 34: 'y', 35: 'z', 36: ':', 37: ';', 38: '<', 39: '=', 40: '>', 41: '?', 42: '@', 43: '[', 44: ']', 45: '^', 46: '_', 47: '{', 48: '|', 49: '}', 50: 'A', 51: 'B', 52: 'C', 53: 'D', 54: 'E', 55: 'F', 56: 'G', 57: 'H', 58: 'I', 59: 'J', 60: 'K', 61: 'L', 62: 'M', 63: 'N', 64: 'O', 65: 'P', 66: 'Q', 67: 'R', 68: 'S', 69: 'T', 70: 'U', 71: 'V', 72: 'W', 73: 'X', 74: 'Y', 75: 'Z'} var twentySix = map[byte]byte{'1': 'A', '2': 'B', '3': 'C', '4': 'D', '5': 'E', '6': 'F', '7': 'G', '8': 'H', '9': 'I', 'a': 'J', 'b': 'K', 'c': 'L', 'd': 'M', 'e': 'N', 'f': 'O', 'g': 'P', 'h': 'Q', 'i': 'R', 'j': 'S', 'k': 'T', 'l': 'U', 'm': 'V', 'n': 'W', 'o': 'X', 'p': 'Y', 'q': 'Z'} func decimalToAny(num, n int) []byte { var newNumStr []byte var remainder int var remainderString byte for num != 0 { remainder = num % n remainderString = tenToAny[remainder] newNumStr = append(newNumStr, remainderString) num = num / n } return newNumStr } ```